3[x+1]=2[x-1]+6

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Solution for 3[x+1]=2[x-1]+6 equation:


Simplifying
3[x + 1] = 2[x + -1] + 6

Reorder the terms:
3[1 + x] = 2[x + -1] + 6
[1 * 3 + x * 3] = 2[x + -1] + 6
[3 + 3x] = 2[x + -1] + 6

Reorder the terms:
3 + 3x = 2[-1 + x] + 6
3 + 3x = [-1 * 2 + x * 2] + 6
3 + 3x = [-2 + 2x] + 6

Reorder the terms:
3 + 3x = -2 + 6 + 2x

Combine like terms: -2 + 6 = 4
3 + 3x = 4 + 2x

Solving
3 + 3x = 4 + 2x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-2x' to each side of the equation.
3 + 3x + -2x = 4 + 2x + -2x

Combine like terms: 3x + -2x = 1x
3 + 1x = 4 + 2x + -2x

Combine like terms: 2x + -2x = 0
3 + 1x = 4 + 0
3 + 1x = 4

Add '-3' to each side of the equation.
3 + -3 + 1x = 4 + -3

Combine like terms: 3 + -3 = 0
0 + 1x = 4 + -3
1x = 4 + -3

Combine like terms: 4 + -3 = 1
1x = 1

Divide each side by '1'.
x = 1

Simplifying
x = 1

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